单选题

暖风机的安装高度当出口风速≤5m/s和>5m/s时,其安装高度分别为()

A. 3~3.5m和4~5.5m
B. 2~2.5m和3~4.5m
C. 4~4.5m和5~6.5m
D. 4~5m和5~6m

查看答案
该试题由用户148****82提供 查看答案人数:18187 如遇到问题请 联系客服
正确答案
该试题由用户148****82提供 查看答案人数:18188 如遇到问题请联系客服

相关试题

换一换
热门试题
5ms双周期帧结构支持的最大广播波束为个() sub6G的5ms单周期帧结构支持波束() 中移采用的5ms单周期下行配置了几个slot?() 鱼骨图将导致不良结果的原因分成5Ms,它是指:()。 爱立信的IP化端局目前切换时使用()编码,打包时长为5ms。 5ms单周期这四种帧结构中,时延最小的是: 爱立信的IP化端局目前切换时使用()编码,打包时长为5ms 假设将SRS的周期从40ms调整到5ms,该优化可以针对如下哪种场景() 二级母钟与一级母钟的同步误差小于5ms() 直达声与经过5ms一35ms后的延时声到达人耳后会感到声音()。 5ms单周期这四种帧结构中,上行覆盖最佳的是: LTE关于时延的设计目标是要满足用户面不大于100ms,控制面不大于5ms() LTE关于时延的设计目标是要满足用户面不大于100ms,控制面不大于5ms() OTUk_LOF为OTUk层告警,表示OTUk帧丢失,对FAS帧对齐开销进行检测,连续5ms处于帧失步状态则上报此告警,在恢复帧同步状态持续5ms后告警结束() 在 Windows 中,运行(请作答此空)命令得到下图所示结果。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds:Minimum = 3ms, Maximum = 5ms, Average = 4ms) 每个子帧的时长为5ms。每一个子帧又分成?() 按照时间基准,定时器分为5ms,10ms,100ms3种类型,不同的时间基准,定时范围和定时器的刷新方式不同() 在 Windows 中,运行( )命令得到下图所示结果。以下关于该结果的叙述中,错误的是( )。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 3ms, Maximum = 5ms, Average = 4ms 在 Windows 中,运行( )命令得到下图所示结果。以下关于该结果的叙述中,错误的是( )。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 3ms, Maximum = 5ms, Average = 4ms 在 Windows 中,运行(请作答此空)命令得到下图所示结果。以下关于该结果的叙述中,错误的是()。Pinging 59.74.111.8 with 32 bytes of data:Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Reply from 59.74.111.8: bytes=32 time=3ms TTL=60Reply from 59.74.111.8: bytes=32 time=5ms TTL=60Ping statistics for 59.74.111.8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 3ms, Maximum = 5ms, Average = 4ms
购买搜题卡 会员须知 | 联系客服
会员须知 | 联系客服
关注公众号,回复验证码
享30次免费查看答案
微信扫码关注 立即领取
恭喜获得奖励,快去免费查看答案吧~
去查看答案
全站题库适用,可用于E考试网网站及系列App

    只用于搜题看答案,不支持试卷、题库练习 ,下载APP还可体验拍照搜题和语音搜索

    支付方式

     

     

     
    首次登录享
    免费查看答案20
    微信扫码登录 账号登录 短信登录
    使用微信扫一扫登录
    登录成功
    首次登录已为您完成账号注册,
    可在【个人中心】修改密码或在登录时选择忘记密码
    账号登录默认密码:手机号后六位