2024年成考高起点《数学(理)》每日一练试题04月16日
聚题库
04/16
<p class="introTit">单选题</p><p>1、在△ABC中，若lgsinA-lgsinB-lgcos=lg2，则△ABC是（）</p><ul><li>A：以A为直角的三角形</li><li>B：b=c的等腰三角形</li><li>C：等边三角形</li><li>D：钝角三角形</li></ul><p>答 案：B</p><p>解 析：判断三角形的形状，条件是用一个对数等式给出先将对数式利用对数的运算法则整理。 ∵lgsinA-lgsinB-lgcos=lg2，由对数运算法则可得,左<img src="https://img2.meite.com/questions/202303/286422954acc4dc.png" />
两个对数底数相等则真数相等：<img src="https://img2.meite.com/questions/202303/2864229567bb0e0.png" />即2sinBcosC=sinA
在△ABC中，∵A+B+C=180°，∴A=180°-（B+C）,
<img src="https://img2.meite.com/questions/202303/28642295c273960.png" /><img src="https://img2.meite.com/questions/202303/28642295c819886.png" /><img src="https://img2.meite.com/questions/202303/28642295d337926.png" /><img src="https://img2.meite.com/questions/202303/28642295d958b6e.png" /><img src="https://img2.meite.com/questions/202303/28642295df5ccdf.png" />
故为等腰三角形</p><p>2、已知复数z=a+bi,其中a,<img src="https://img2.meite.com/questions/202303/2864224cfda7e7d.png" />且b≠0，则（）
</p><ul><li>A：<img src='https://img2.meite.com/questions/202303/2864224d5102575.png' /></li><li>B：<img src='https://img2.meite.com/questions/202303/2864224d5d6afe7.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/2864224d6343bc7.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/2864224d6ad6d12.png' /></li></ul><p>答 案：C</p><p>解 析：注意区分<img src="https://img2.meite.com/questions/202303/2864224f432bb09.png" /> <img src="https://img2.meite.com/questions/202303/2864224f5bec577.png" />
</p><p>3、设甲：<img src="https://img2.meite.com/questions/202303/15641165369dc0c.png" />；乙：<img src="https://img2.meite.com/questions/202303/156411653e04dd6.png" />.则（）</p><ul><li>A：甲是乙的必要条件但不是充分条件</li><li>B：甲是乙的充分条件但不是必要条件</li><li>C：甲是乙的充要条件</li><li>D：甲既不是乙的充分条件也不是乙的必要条件</li></ul><p>答 案：A</p><p>解 析：三角形相似不一定全等，但三角形全等一定相似，因此，甲是乙的必要条件但不是充分条件．</p><p>4、在△ABC中,已知2B= A+C,<img src="https://img2.meite.com/questions/202303/2864224869b5896.png" />= ac,则B-A=（）
</p><ul><li>A：0</li><li>B：<img src='https://img2.meite.com/questions/202303/286422487fede7b.png' /></li><li>C：<img src='https://img2.meite.com/questions/202303/286422488835324.png' /></li><li>D：<img src='https://img2.meite.com/questions/202303/286422488c2a04f.png' /></li></ul><p>答 案：A</p><p>解 析：在△ABC中,A+B+C=π，A+C=π-B，① 因为2B=A+C，②
由①②得2B=π-B，<img src="https://img2.meite.com/questions/202303/28642249c382987.png" />
<img src="https://img2.meite.com/questions/202303/28642249ca97aad.png" /><img src="https://img2.meite.com/questions/202303/28642249d5a95b9.png" />
<img src="https://img2.meite.com/questions/202303/28642249df58afe.png" />
由③④得<img src="https://img2.meite.com/questions/202303/28642249f0592a4.png" />a=c。所以A=C，又<img src="https://img2.meite.com/questions/202303/2864224a1878921.png" />所以△ABC为等边三角形，则B-A=0
</p><p class="introTit">主观题</p><p>1、建筑一个容积为8000<img src="https://img2.meite.com/questions/202303/2864224b406cbf6.png" />,深为6m的长方体蓄水池，池壁每<img src="https://img2.meite.com/questions/202303/2864224b5cac16d.png" />的造价为15元，池底每<img src="https://img2.meite.com/questions/202303/2864224b60ac28e.png" />的造价为30元。（I）把总造价y(元)表示为长x(m)的函数；（Ⅱ）求函数的定义域
</p><p>答 案：<img src="https://img2.meite.com/questions/202303/2864224be4311f4.png" /><img src="https://img2.meite.com/questions/202303/2864224bee67713.png" /></p><p>2、设函数f(x)=xlnx+x.(I）求曲线y=f(x）在点（(1,f(1))处的切线方程；<br />(II）求f（x）的极值．</p><p>答 案：(I）f(1)=1,f'(x)=2+lnx，故f'(1)=2.所以曲线y=f(x）在点（1,f(1))处的切线方程为y=2x-1.(II）令f'(x)=0，解得<img src="https://img2.meite.com/questions/202303/1564116d2d14a94.png" />当<img src="https://img2.meite.com/questions/202303/1564116d3d33026.png" />时，f'(x)<O；当<img src="https://img2.meite.com/questions/202303/1564116d6f6aec3.png" />时，f'(x)＞O.故f(x）在区间<img src="https://img2.meite.com/questions/202303/1564116db9a0764.png" />单调递减，在区间<img src="https://img2.meite.com/questions/202303/1564116dc99fc91.png" />单调递增．因此f(x）在<img src="https://img2.meite.com/questions/202303/1564116ddb842d0.png" />时取得极小值<img src="https://img2.meite.com/questions/202303/1564116de4f1b79.png" /></p><p>3、在正四棱柱ABCD-A'B'C'D'中，<img src="https://img2.meite.com/questions/202303/2864229a3bc3098.png" />
（Ⅰ）写出向量<img src="https://img2.meite.com/questions/202303/2864229a57ba174.png" />和<img src="https://img2.meite.com/questions/202303/2864229a5e46ac8.png" />关于基底{a,b,c}的分解式;
（Ⅱ）求证：<img src="https://img2.meite.com/questions/202303/2864229a76ba56d.png" />
（Ⅲ）求证：<img src="https://img2.meite.com/questions/202303/2864229a7fdd541.png" />
</p><p>答 案：（Ⅰ）由题意知(如图所示) <img src="https://img2.meite.com/questions/202303/2864229af6b1567.png" />
<img src="https://img2.meite.com/questions/202303/2864229afe90f50.png" />
<img src="https://img2.meite.com/questions/202303/2864229b08314c5.png" />
</p><p>4、在△ABC中，B=120°,BC=4,△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />，求AC.</p><p>答 案：由△ABC的面积为<img src="https://img2.meite.com/questions/202303/15641165ec55404.png" />得<img src="https://img2.meite.com/questions/202303/1564116bba3c98d.png" />所以AB =4.因此<img src="https://img2.meite.com/questions/202303/1564116be4bebd5.png" />所以<img src="https://img2.meite.com/questions/202303/1564116be967e8f.png" /></p><p class="introTit">填空题</p><p>1、函数<img src="https://img2.meite.com/questions/202303/2864225857f0d64.png" />的图像与坐标轴的交点共有（）
</p><p>答 案：2</p><p>解 析：当x=0时，y=<img src="https://img2.meite.com/questions/202303/286422587f2a68b.png" />-2=-1，故函数与y轴交于(0,-1)点，令y=0,则有<img src="https://img2.meite.com/questions/202303/28642258b372965.png" />故函数与x轴交于(1,0) 点,因此函数 <img src="https://img2.meite.com/questions/202303/28642258c6c51c8.png" />与坐标轴的交点共有 2个.</p><p>2、不等式<img src="https://img2.meite.com/questions/202303/28642289d6ca884.png" />的解集为（）
</p><p>答 案：<img src="https://img2.meite.com/questions/202303/28642289e5c9bcc.png" /></p><p>解 析：<img src="https://img2.meite.com/questions/202303/28642289efc4ba4.png" /><img src="https://img2.meite.com/questions/202303/28642289fa37c87.png" /><img src="https://img2.meite.com/questions/202303/2864228a0077853.png" /></p>
